log[3](1-x)=1+log[3](x+11)

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Solution for log[3](1-x)=1+log[3](x+11) equation:


Simplifying
log[3](1 + -1x) = 1 + log[3](x + 11)

Reorder the terms for easier multiplication:
3glo(1 + -1x) = 1 + log[3](x + 11)
(1 * 3glo + -1x * 3glo) = 1 + log[3](x + 11)
(3glo + -3glox) = 1 + log[3](x + 11)

Reorder the terms:
3glo + -3glox = 1 + glo * 3(11 + x)

Reorder the terms for easier multiplication:
3glo + -3glox = 1 + 3glo(11 + x)
3glo + -3glox = 1 + (11 * 3glo + x * 3glo)
3glo + -3glox = 1 + (33glo + 3glox)

Solving
3glo + -3glox = 1 + 33glo + 3glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-33glo' to each side of the equation.
3glo + -33glo + -3glox = 1 + 33glo + -33glo + 3glox

Combine like terms: 3glo + -33glo = -30glo
-30glo + -3glox = 1 + 33glo + -33glo + 3glox

Combine like terms: 33glo + -33glo = 0
-30glo + -3glox = 1 + 0 + 3glox
-30glo + -3glox = 1 + 3glox

Add '-3glox' to each side of the equation.
-30glo + -3glox + -3glox = 1 + 3glox + -3glox

Combine like terms: -3glox + -3glox = -6glox
-30glo + -6glox = 1 + 3glox + -3glox

Combine like terms: 3glox + -3glox = 0
-30glo + -6glox = 1 + 0
-30glo + -6glox = 1

Reorder the terms:
-1 + -30glo + -6glox = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -30glo + -6glox = 0

Factor out the Greatest Common Factor (GCF), '-1'.
-1(1 + 30glo + 6glox) = 0

Ignore the factor -1.

Subproblem 1

Set the factor '(1 + 30glo + 6glox)' equal to zero and attempt to solve: Simplifying 1 + 30glo + 6glox = 0 Solving 1 + 30glo + 6glox = 0 Move all terms containing g to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + 30glo + -1 + 6glox = 0 + -1 Reorder the terms: 1 + -1 + 30glo + 6glox = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 30glo + 6glox = 0 + -1 30glo + 6glox = 0 + -1 Combine like terms: 0 + -1 = -1 30glo + 6glox = -1 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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